Odpowiedź:
12.
a) [tex](\frac{3}{4})^{-1}+(\frac{1}{3})^{-2}=\frac{4}{3}+\frac{9}{1} =\frac{4}{3}+\frac{27}{3}= \frac{31}{3} = 10\frac{1}{3}[/tex]
b) [tex]2^{5}-(3^{2} -2^3)=2^5-3^2+2^3=32-9+8=31[/tex]
c) [tex]\sqrt[3]{27*64} = \sqrt[3]{1728} = 12[/tex]
13.
[tex]P = \frac{1}{2}*a*h[/tex]
[tex]P = \frac{1}{2}*1,2*10^5*3*10^3[/tex]
[tex]P = \frac{1}{2}*3,6*10^8[/tex]
[tex]P = 1,8*10^8[/tex]
14.
[tex]a = (3^3)^5\\b = (3^6)^2[/tex]
[tex]a = 3^{15}\\b = 3^{12}[/tex]
[tex]a*b=3^{15}*3^{12}=3^{27}[/tex]
Szczegółowe wyjaśnienie:
