Odpowiedź:
a)
[tex]\left \{ {{x^{2} +y^{2}-6y+5=0 } \atop {x^{2} +y^{2}-6x-6y+17=0 }} \right. \\\left \{ {{x^{2}+y^{2}-6y=-5 } \atop {x^{2} +y^{2}-6x-6y=-17 }} \right.\\ \left \{ {{x^{2}+y^{2}-6y=-5 } \atop {-x^{2} -y^{2}+6x+6y=17 }} \right.\\ 6x=12\\x=2\\2^{2}+y^{2}-6y=-5\\ y=3\\ (x,y)=(2,3)\\\left \{ {{2^{2}+3^{2}-6x3+5=0 } \atop {2^{2}+3^{2}-6x2-6x3+17=0 }} \\\left \{ {{0=0} \atop {0=0}} \right.\\ (x,y)=(2,3)\\[/tex]
Szczegółowe wyjaśnienie:
