1.
[tex]Dane:\\S = 0,35 \ m^{2}\\F = 20 \ N\\Szukane:\\p = ?\\\\\\p = \frac{F}{S}\\\\p = \frac{20 \ N}{0,35 \ m^{2}}\\\\\boxed{p\approx57,14 \ Pa}[/tex]
2.
[tex]Dane:\\F = 1,75 \ N\\S = 15 \ cm^{2} = 0,0015 \ m^{2}\\Szukane:\\p = ?\\\\\\p =\frac{F}{S}\\\\p = \frac{1,75 \ N}{0,0015 \ m^{2}}\\\\p = 1 \ 166,(6) \ Pa\\\\\boxed{p \approx1 \ 166,67 \ Pa}[/tex]