Odpowiedź:
1.
b)
d - średnica podstawy = 6 cm
H - wysokość walca = 8 cm
Pp = πd²/4 = π * 6² cm² : 4 = 36π/4 cm² = 9π cm²
Pb = πdH = π * 6 cm * 8 cm = 48π cm²
Pc = 2 * Pp + Pb = 2 * 9π cm² + 48π cm² = 18π cm² + 48π cm² = 66π cm²
V = Pp * H = 9π cm² * 8 cm = 72π cm³
c)
r - promień podstawy = 4 cm
H - wysokość walca = 5 cm
Pp = πr² = π * 4² cm² = 16π cm²
Pb = 2πrH = 2π * 4 cm * 5 cm = 40π cm²
Pc = 2 * Pp + Pb = 2 * 16π cm² + 40π cm² = 32π cm² + 40π cm² = 72π cm²
V = Pp * H = 16π cm² * 5 cm = 80π cm³
