Odpowiedź:
1.
A) CaO=mCa:mO= 40u :16u = 5 :2
B) CuS= mCu : mS =64u :32u= 2: 1
C) Cu2O= mCu: mO = 2*64u :16u= 128u :16u= 8: 1
D) NaOH =mNa:mO :mH= 23u :16u :1u =23:16:1
E) H2CO3=mH; mC:mO=2*1u: 12u : 3*16u= 2u:12u:48u= 1 : 6 : 24
2
A) CaO
M CaO= 40g +16g=56g
56g-----100% 56g--------100%
40g --- x 16g ------- x
x= 71,43%Ca x=28,57%O
B) CuS
M CuS= 64g+32g=96g
96g-----100% 96g--------100%
64g ---- x 32g ------ x
x= 66,7%Cu x= 33,3%O
C) Cu2O
MCu2O=2*64g+16g=128g +16g=144g
144g----100% 144g-----100%
128g---- x 16g ----- x
x= 88,9 %Cu x= 11,1%O
D) NaOH
MNaOH= 23g +16g +1g=40g
40g -----100% 40g------100% 40g--------100%
23g---- x 16g ----- x 1g ------ x
x=57,5%Na x=40,0%O x= 2,5%H
E) H2CO3
M H2CO3 = 2g +12g+48g= 62u
62g -------100% 62g--------100% 62g--------100%
2g ------ x 12g ---- x 48g ------- x
x= 3,2%H x= 19,4%C x= 77,4%O
