Odpowiedź:
a) CH3CH2CH2Cl +NaOH--> CH3CH3CH2OH +NaCl
b) CH3CHO +Ag2O --> CH3COOH + 2Ag
c) CH3COOH +NH2-->CH3COO-NH4---TEMP.-->CH3CONH2
d) HCOOH +C3H7OH --> HCOOC3H7+ H2O
reakcje spalania:
a) 2C2H4(OH)2 +5O2 --> 4CO2 +6H2O
b) 2C17H33COOH + 49O2--> 34CO2 + 34H2O
IZOMERY:C4H8O
CH3CH2CH2CHO butanal/aldehyd butanowy/
CH3-CH2-C- CH3 butan-2-on
II
O
CH3-CH-CHO 2metylopropanal
I
CH3
CH2CH2CHO 3-metylopropanal
I
CH3