Odpowiedź:
1)
[tex] {a}^{2} = ( {2 \sqrt{3} })^{2} + {2}^{2} [/tex]
[tex] {a}^{2} = 4 \times 3 + 4[/tex]
[tex] {a}^{2} = 12 + 4[/tex]
[tex] {a}^{2} = 16[/tex]
[tex]a = \sqrt{16} =4[/tex]
[tex] {b}^{2} = ( {2 \sqrt{3} })^{2} + {3}^{2} [/tex]
[tex] {b}^{2} = 12 + 9[/tex]
[tex] {b}^{2} = 21[/tex]
[tex]b = \sqrt{21} [/tex]
2)
[tex] {c}^{2} = {20}^{2} - {12}^{2} [/tex]
[tex] {c}^{2} = 400 - 144[/tex]
[tex] {c}^{2} = 256[/tex]
[tex]c = \sqrt{256} = 16[/tex]
[tex] {d}^{2} = {13}^{2} - {12}^{2} [/tex]
[tex] {d}^{2} = 169 - 144[/tex]
[tex] {d}^{2} = 25[/tex]
[tex]d = 5[/tex]
