Odpowiedź:
a) [tex]\frac{12-x}{4} = \frac{x+4}{12} \\[/tex] I*12
[tex]\frac{12}{1} * \frac{12-x}{4} = x +4\\[/tex]
3 * (12 - x) = x +4
36 - 3x = x +4
-3x - x = 4 - 36
-4x = - 32
-x = - 8
x = 8
b) [tex]\frac{3x-2}{4} = \frac{4x - 5}{3}[/tex] I*12
[tex]\frac{12}{1} * \frac{3x-2}{4} = \frac{12}{1} * \frac{4x-5}{3}[/tex]
3 * (3x - 2) = 4* (4x-5)
9x - 6 + 16x - 20
9x - 16 = -20 +6
7x = - 14
x = -2
c) [tex]\frac{x-3}{6} = 2(3x +1)[/tex]
[tex]\frac{x-3}{6} = 6x +2[/tex] I*6
x - 3 = 6 (6x +2)
x - 3 = 36 + 12
-3 - 12 = 36x - x
- 15 = 35x
x = [tex]-\frac{15}{35} = -\frac{3}{7}[/tex]
d) 3 (1 - [tex]\frac{x}{3}[/tex]) = [tex]\frac{5x-1}{9}[/tex] I*9
27 - 9x = 5x - 1
27 + 1 = 5x + 9x
28 = 14x
x = 2
Szczegółowe wyjaśnienie: