Ogólnie w tym zadaniu chodzi o podstawienie punktów do wzoru funkcji i rozwiązanie równań.
a)
[tex]9a-2*15=15\\9a-30=15\\9a=15+30\\9a=45\ |:9\\a=5\\\\9*(-17)-2b=15\\-153-2b=15\\-2b=15+153\\-2b=168\ |:(-2)\\b=-84[/tex]
b)
[tex]\frac{1}{5}*3\frac{3}{4}-\frac{2}{5}a=0,6\\\frac{1}{5}*\frac{15}{4}-\frac{2}{5}a=\frac{3}{5}\\\frac{3}{4}-\frac{2}{5}a=\frac{3}{5}\ |*20\\15-8a=12\\-8a=12-15\\-8a=-3\ :(-8)\\a=\frac{3}{8}\\\\\frac{1}{5}b-\frac{2}{5}*(-6)=0,6\\\frac{1}{5}b+\frac{12}{5}=\frac{3}{5}\ |*5\\b+12=3\\b=3-12\\b=-9[/tex]
c)
[tex]0,3*(-6)-0,5a=1,2\\-1,8-0,5a=1,2\ |*(-10)\\18+5a=-12\\5a=-12-18\\5a=-30\ |:5\\a=-6\\\\0,3b-0,5*9=1,2\\0,3b-4,5=1,2\ |*10\\3b-45=12\\3b=12+45\\3b=57\ |:3\\b=19[/tex]
d)
[tex]5\sqrt2a-\frac{2}{3}*120=0\\5\sqrt2a-80=0\\5\sqrt2a=80\ |:5\sqrt2\\a=\frac{80}{5\sqrt2}\\a=\frac{16}{\sqrt2}*\frac{\sqrt2}{\sqrt2}\\a=\frac{16\sqrt2}{2}\\a=8\sqrt2\\\\5\sqrt2b-\frac{2}{3}*(-21)=0\\5\sqrt2a+14=0\\5\sqrt2a=-14\ |:5\sqrt2\\a=-\frac{14}{5\sqrt2}*\frac{\sqrt2}{\sqrt2}\\a=-\frac{14\sqrt2}{10}\\a=-\frac{7\sqrt2}{5}[/tex]
