Odpowiedź:
[tex]\begin{cases}\frac{x-1}{2}+\frac{y+1}{3}=3\ \ /\cdot6\\\frac{x+1}{3}-\frac{y-2}{6}=2\ \ /\cdot6\end{cases}\\\\\\\begin{cases}3(x-1)+2(y+1)=18\\2(x+1)-(y-2)=12\end{cases}\\\\\\\begin{cases}3x-3+2y+2=18\\2x+2-y+2=12\end{cases}\\\\\\\begin{cases}3x-1+2y=18\\2x+4-y=12\end{cases}\\\\\\\begin{cases}3x+2y=18+1\\2x-y=12-4\end{cases}\\\\\\\begin{cases}3x+2y=19\\2x-y=8\ \ /\cdot2\end{cases}\\\\\\+\begin{cases}3x+2y=19\\4x-2y=16\end{cases}\\---------\\7x=35\ \ /:7\\x=5[/tex]
[tex]2\cdot5-y=8\\\\10-y=8\\\\-y=8-10\\\\-y=-2\ \ /\cdot(-1)\\\\y=2\\\\\begin{cases}x=5\\y=2\end{cases}[/tex]
