zad.1
50 zł - 19,20 zł = 30,80 zł
30,80 ÷ 7 = 4,40 zł
4,40 zł - cena jednej czekolady
zad.2
[tex](2^{3} \cdot (\frac{1}{2} )^{3} )^{2} =((2\cdot \frac{1}{3} )^{2} )^{2} =(1^{3} )^{2} =1^{3\cdot 2} =1^{6} =1\\\\3^{3} \cdot (\frac{2}{3} )^{2} =27\cdot \frac{4}{9} =3\cdot 4 = 12\\\\(2^{3} \cdot (\frac{1}{2} )^{3} )^{2} + 3^{3} \cdot (\frac{2}{3} )^{2} = 1+12 =13[/tex]
