Odpowiedź :
[tex]\frac{x^2 - 2x}{3}[/tex] dla x = -6
[tex]\frac{(-6)^2 - 2*(-6)}{3} = \frac{36- (-12)}{3} = \frac{36+12}{3} = \frac{48}{3} = 16[/tex]
Gdyby było [tex]\frac{2x}{3}[/tex] to:
[tex](-6)^2 - \frac{2*(-6)}{3} = 36 + 4 = 40[/tex]
[tex]\frac{x^2 - 2x}{3}[/tex] dla x = -6
[tex]\frac{(-6)^2 - 2*(-6)}{3} = \frac{36- (-12)}{3} = \frac{36+12}{3} = \frac{48}{3} = 16[/tex]
Gdyby było [tex]\frac{2x}{3}[/tex] to:
[tex](-6)^2 - \frac{2*(-6)}{3} = 36 + 4 = 40[/tex]