Odpowiedź:
a)
CH2=CH-CH2-CH2-CH3 +HBr--> CH3-CHBr-CH2-CH2-CH3
pent-1-en + bromowodór --> 2-bromopentan
b)
CH3 CH3
I I
/ \ / \_ CH3
I O I + CH3Cl --> I O I + HCl
\ / \ /
metylobenzen 1,2- dimetylobenzen
