[tex]\dfrac{1}{6} H=\dfrac{4}{24} H\\\\\dfrac{5}{8} H=\dfrac{15}{24} H\\\\\\\dfrac{1}{6} H + 440l=\dfrac{5}{8} H\\\\\dfrac{4}{24} H+440l=\dfrac{15}{24} H\\\\\dfrac{15}{24} H-\dfrac{4}{24} H=440l\\\\\dfrac{11}{24} H=440l~~\mid \div \dfrac{11}{24} \\\\H=960l\\\\Odp:~~W~~zbiorniku~~miesci~~sie~~960l.[/tex]