Zad 1
[tex]a) \frac{2}{3}+\frac{1}{5}= \frac{10}{15} + \frac{3}{15} = \frac{13}{15}[/tex]
[tex]b) \frac{5}{6} - \frac{3}{4} = \frac{10}{12} - \frac{9}{12} = \frac{1}{12}[/tex]
[tex]c)\frac{7}{20} -\frac{1}{4} = \frac{7}{20}-\frac{5}{20} = \frac{2}{20} =\frac{1}{10}[/tex]
Zad 2
[tex]a) 5\frac{1}{4} -2\frac{1}{6} = 5\frac{3}{12} - 2\frac{2}{12} = 3\frac{1}{12}[/tex]
[tex]b) 4\frac{1}{3} +2\frac{1}{6} = 4\frac{2}{6} +2\frac{1}{6} = 6\frac{3}{6} = 6\frac{1}{2}[/tex]
[tex]c) 4\frac{1}{2} -1\frac{3}{4} = 4\frac{2}{4} - 1\frac{3}{4} =2\frac{3}{4}[/tex]
Zad 3
[tex]1\frac{3}{4}l-\frac{1}{3} l=1\frac{9}{12} l -\frac{4}{12} l= 1\frac{5}{12} l[/tex]
Odp: W dzbanku zostało [tex]1\frac{5}{12}[/tex] litra soku.
