Odpowiedź:
[tex]4.\\\\-(2-a^2+4a)=-2+a^2-4a\\\\Odp.C\\\\\\5.\\\\2x(3x-5)=2x\cdot3x-2x\cdot5=6x^2-10x\\\\Odp.C\\\\\\6.\\\\(5x-3)(2x+2)-(x+4)(3-x)=10x^2+10x-6x-6-(3x-x^2+12-4x)=\\\\=10x^2+4x-6-3x+x^2-12+4x=11x^2+5x-18\\\\\\dla\ \ x=-1\\\\11x^2+5x-18=11\cdot(-1)^2+5\cdot(-1)-18=11\cdot1-5-18=11-23=-12[/tex]