Odpowiedź:
[tex]a)\\\\6x=3\ \ /:6\\\\x=\frac{3}{6}\\\\x=\frac{1}{2}\\\\\\b)\\\\2x=\frac{1}{5}\ \ /:2\\\\x=\frac{1}{5}\cdot\frac{1}{2}\\\\x=\frac{1}{10}\\\\\\e)\\\\\frac{1}{3}x=3\ \ /:\frac{1}{3}\\\\x=3\cdot3\\\\x=9\\\\\\g)\\\\\frac{3}{4}x=-\frac{4}{9}\ \ /:\frac{3}{4}\\\\x=-\frac{4}{9}\cdot\frac{4}{3}\\\\x=-\frac{16}{27}[/tex]
