1.
[tex]Dane:\\n = 5\\t = 1 \ min = 60 \ s\\Szukane:\\f = ?\\T = ?[/tex]
Rozwiązanie
Częstotliwość obrotu:
[tex]f = \frac{n}{t}\\\\f = \frac{5}{60 \ s}\\\\\boxed{f \approx0,083 \ Hz}[/tex]
Okres obrotu:
[tex]T = \frac{t}{n}\\\\T = \frac{60 \ s}{5}\\\\\boxed{T = 12 \ s}[/tex]
2.
[tex]Dane:\\m = 0,5 \ kg\\60\frac{km}{h} = 60\cdot\frac{1000 \ m}{3600 \ s} = 16,(6)\frac{m}{s} \approx16,67\frac{m}{s}\\d = 50 \ cm \ \ \rightarrow \ \ r = 25 \ cm = 0,25 \ m\\Szukane:\\F_{d}= ?\\\\Rozwiazanie\\\\F_{d} = \frac{mv^{2}}{r}\\\\F_{d} = \frac{0,5 \ kg \cdot(16,67\frac{m}{s})^{2}}{0,25 \ m}\\\\\boxed{F_{d}\approx555,8 \ N}[/tex]
