a)
[tex]16-a=9\\\\a=16-9\\\\\boxed{a=7}[/tex]
b)
[tex]8\frac{1}{5}+c=10\frac{7}{10}\\\\c=10\frac{7}{10}-8\frac{1}{5}=10\frac{7}{10}-8\frac{2}{10}=2\frac{5}{10}\\\\\boxed{c=2\frac{1}{2}}[/tex]
c)
[tex]4\frac{2}{3}\cdot p=4\\\\p=4:4\frac{2}{3}=4:\frac{14}{3}=4\cdot\frac{3}{14}=2\cdot\frac{3}{7}\\\\\boxed{p=\frac{6}{7}}[/tex]
d)
[tex]a:1\frac{1}{3}=\frac{1}{6}\\\\a=\frac{1}{6}\cdot1\frac{1}{3}=\frac{1}{\not6_3}\cdot\frac{\not4^2}{3}\\\\\boxed{a=\frac{2}{9}}[/tex]