[tex]Dane:\\m = 3 \ kg\\h_1 = 6 \ m\\h_2 = 2 \ m\\\Delta h = h_1-h_2 = 6 \ m - 2 \ m = 4 \ m\\g = 10\frac{N}{kg}\\Szukane:\\W = ?\\\\Rozwiazanie\\\\W = \Delta E_{p} = m\cdot g\cdot \Delta h\\\\W = m\cdot g \cdot \Delta h\\\\W = 3 \ kg\cdot 10\frac{N}{kg}\cdot4 \ m\\\\\boxed{W = 120 \ J}[/tex]
Odp. Należy wykonac pracę W = 120 J.
