Odpowiedź:
[tex]a)\\(7-5\frac{2}{5})x\frac{1}{4}\\ (7-\frac{27}{5})x\frac{1}{4}\\ \frac{8}{5}x\frac{1}{4}=\frac{2}{5}[/tex]
[tex]b)\\(\frac{7}{9}-\frac{47}{72}):1\frac{1}{4}\\ \frac{1}{8}:\frac{5}{4}\\ \frac{1}{8}x\frac{4}{5}\\ \frac{1}{2}x\frac{1}{5}=\frac{1}{10}\\[/tex]
[tex]c)\\6x(1\frac{1}{3})^{2}\\ 6x(\frac{4}{3})^{2}\\ 6x\frac{16}{9}\\ 2x\frac{16}{3}=\frac{32}{3}=10\frac{2}{3}[/tex]
[tex]d)\\(\frac{5}{7})^{2}:\frac{5}{7}\\ (\frac{5}{7})^{2}x(\frac{5}{7})^{-1}\\ (\frac{5}{7})^{2-1}\\ ( \frac{5}{7})^{1}\\ \frac{5}{7}\\[/tex]
[tex]e)\\(\frac{1}{3}-\frac{1}{4})^{2}\\ (\frac{1}{12})^{2}=\frac{1}{144}[/tex]
[tex]f)\\(\frac{2}{5})^{2}+4\frac{1}{2}x2\frac{2}{3}\\ \frac{4}{25}+\frac{9}{2}x\frac{8}{3}\\ \frac{4}{25}+3x4\\ \frac{4}{25}+12\\ \frac{304}{25}=12\frac{4}{25}[/tex]
[tex]g)\\5x(\frac{1}{2}^{2}+15x(\frac{1}{3})^{2}\\ 5x\frac{1}{4}+15x\frac{1}{9}\\ \frac{5}{4}+5x\frac{1}{3}\\ \frac{5}{4}+\frac{5}{3}\\ \frac{35}{12}=2\frac{11}{12}[/tex]
[tex]h)\\\frac{1}{9}-(\frac{5}{6}-\frac{2}{3})^{2}\\ \frac{1}{9}-(\frac{1}{6})^{2}\\ \frac{1}{9}-\frac{1}{36}\\ \frac{1}{12}[/tex]
Szczegółowe wyjaśnienie:
