Oblicz mase kulki, która pod wpływem siły 6N uzyskuje przyśpieszenie.
![Oblicz Mase Kulki Która Pod Wpływem Siły 6N Uzyskuje Przyśpieszenie class=](https://pl-static.z-dn.net/files/df1/a55fc0e8737f01caa3e9edc136223d8a.png)
Zad. 4
[tex]Dane:\\F = 6 \ N\\a = 6\frac{m}{s^{2}} = 6\frac{N}{kg}\\Szukane:\\m = ?\\\\F = m\cdot a \ \ /:a\\\\m = \frac{F}{a}\\\\m = \frac{6 \ N}{6\frac{N}{kg}}\\\\\boxed{m = 1 \ kg}[/tex]
Zad. 5
[tex]dane:\\m = 5 \ kg\\a = 2\frac{m}{s^{2}}\\Szukane:\\F = ?\\\\F = m\cdot a\\\\F = 5 \ kg\cdot2\frac{m}{s^{2}}\\\\\boxed{F = 10 \ N}[/tex]
Zad.***
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F [N] 2 4 6 8
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a [m/s²] 4 8 12 16
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[tex]m = \frac{F}{a} = \frac{2 \ N}{4\frac{m}{s^{2}}}=0,5 \ kg\\\\a = \frac{F}{m} = \frac{4 \ N}{0,5 \ kg} = 8\frac{m}{s^{2}}\\\\F = m\cdot a = 0,5 \ kg\cdot12\frac{m}{s^{2}} = 6 \ N\\\\a = \frac{F}{m} = \frac{8 \ N}{0,5 \ kg} = 16\frac{m}{s^{2}}[/tex]