a) 2log5 - 1 = log25 - log10 = log(25/10) = log2,5
b) 0,5(1+3log₃2) = 0,5(log₃3+log₃2³) = 0,5[log₃(3*8)] = 0,5(log₃24) = log₃√24 = log₃2√6
c) 2/3log₅27 + 2/5log₅32 = log₅∛27² + log₅(5)√32² = log₅(∛27²*(5)√32²) = log₅(9 * 4) = log₅36
d) 12/5log₃∛2 - 3/2log₃∛4 = log₃(5)√2⁴ - log√4 = log₃((5)√2⁴/√4) = log₃((5)√2⁴/2) = log₃((5)√16 / 2) = log₃((5)√16/32) = log₃((5)√2)
(5)√x -> oznacza pierwiastek piątego stopnia z liczby x
