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Proszę o pomoc!!!!!!!!!



Proszę O Pomoc class=

Odpowiedź :

ZAD 4

P(-8√3 ; -5) ; α = 30°

a = tgα = tg30° = √3/3

-5 = -8√3 * √3/3 + b

-5 = -24/3+b

-5 = -8+b

b = 3

y = x√3/3 + 3

a) P(6√3 ; -1) ; α = 30°

y = ax + b

a = tgα = tg30° = √3/3

-1 = 6√3* √3/3 + b

-1 = 18/3 + b

-1 = 6 + b

b = -7

y = x√3/3 - 7

b) P(√3 ; 2) ; α = 60°

y = ax + b

a = tgα = tg60° = √3

2 = √3*√3 + b

2 = 3+b

b = -1

y = √3x - 1

ZAD 5

P(-5;4)

równoległej do prostej: y = -2x + 1

4 = -5a + b

a = (4-b)/-5

a₁ = a₂

-2 = (4-b)/-5

10 = 4 - b

b = -6

a = (4 -(-6))/-5 = 10/-5 = -2

y = -2x - 6