[tex]zad.2)\\\\x=-3\\\\a)\\\\\frac{x+3}{x}=\frac{-3+3}{-3}=\frac{0}{-3}=0\\\\b)\\\\-5x^2-x=-5*(-3)^2-(-3)=-5*9+3=-45+3=-42\\\\c)\\\\-2x+5=-2*(-3)+5=6+5=11\\\\d)\\\\\frac{x+1}{x-1}=\frac{-3+1}{-3-1}=\frac{-2}{-4}=\frac{1}{2}[/tex]
