[tex]a)\\\\2x=5\ \ |:2\\\\x=\frac{5}{2}\\\\\\a+a+a=9\\\\3a=9\ \ |:3\\\\a=3\\\\\\c*c*c=27\\\\c^3=27\\\\c=\sqrt[3]{27}\\\\c=3[/tex]
[tex]b)\\\\15-x=7\frac{1}{3}\\\\-x=7\frac{1}{3}-15\\\\-x=-7\frac{2}{3}\ \ |*(-1)\\\\x=7\frac{2}{3}\\\\\\m-1\frac{5}{6}=2\frac{2}{3}\\\\m=2\frac{4}{6}+1\frac{5}{6}\\\\m=3\frac{9}{6}=4\frac{3}{6}=4\frac{1}{2}[/tex]
[tex]8\frac{5}{8}+\frac{1}{2}b=15\frac{1}{4}\\\\\frac{1}{2}b=15\frac{2}{8}-8\frac{5}{8}\\\\\frac{1}{2}b=14\frac{10}{8}-8\frac{5}{8}\\\\\frac{1}{2}b=6\frac{5}{8}\\\\\frac{1}{2}b=\frac{53}{8}\ \ |*2\\\\b=\frac{53}{4}=13\frac{1}{4}[/tex]
[tex]c)\\\\25:b=6\\\\\frac{25}{b}=6\ \ \ b\neq 0\\\\6b=25\ \ |:6\\\\b=\frac{25}{6}=4\frac{1}{6}\\\\\\d:4=5\frac{1}{2}\\\\\frac{d}{4}=\frac{11}{2}\\\\2d=44\ \ |:2\\\\d=22[/tex]
[tex]6:c=1\frac{1}{2}\\\\\frac{6}{c}=\frac{3}{2}\ \ \ \ c\neq 0\\\\3c=12\ \ |:3\\\\c=4[/tex]
