[tex] \sqrt{1 + \frac{25}{144} } = \sqrt{ \frac{169}{144} } = \frac{13}{12} = 1 \frac{1}{12} [/tex]
[tex] \sqrt[3]{3 + \frac{3}{8} } = \sqrt[3]{ \frac{27}{8} } = \frac{3}{2} = 1 \frac{1}{2} [/tex]
BC
