Odpowiedź:
a)
[tex]\frac{1}{\sqrt{12} + \sqrt{3} } = \frac{1}{\sqrt{12} + \sqrt{3} } * \frac{\sqrt{12} - \sqrt{3} }{\sqrt{12} - \sqrt{3} } = \frac{\sqrt{12} - \sqrt{3} }{12-3} = \frac{\sqrt{12} - \sqrt{3} }{9} = \frac{2\sqrt{3} - \sqrt{3} }{9} = \frac{\sqrt{3} }{9}[/tex]
Pozdro :))
