Odpowiedź:
1.1
b)
bₙ = 3ⁿ
a₁ = 3¹ = 3
a₂ = 3² = 9
a₃ = 3³ = 27
d)
dₙ = nⁿ
a₁ = 1¹ = 1
a₂ = 2² = 4
a₃ = 3³ = 27
e)
eₙ = (5n - 3)/(n + 1)
a₁ = (5 * 1 - 3)/(1 + 1) = (5 - 3)/2= 2/2 = 1
a₂ = (5 * 2 - 3)/(2 + 1) = ( 10 - 3)/3 = 7/3 = 2 1/3
a₃ = (5 * 3 - 3)/(3+ 1) = (15 - 3)/4 = 12/4 = 3
f)
fₙ = 6 - n²
a₁ = 6 - 1² = 6 - 1 = 5
a₂ = 6 - 2² = 6 - 4 = 2
a₃ = 6 - 3² = 6 - 9 = - 3
h)
hₙ = √(n² + 2n + 1) = √(n + 1)²
a₁ = √(1 + 1)² = √2² = 2
a₂ = √(2 + 1)² = √3² = 3
a₃ = √(3 + 1)² = √4² = 4