3.
Obliczmy pole
[tex] \frac{15 \times 20}{2} = 15 \times 10 = 150 {cm}^{2} [/tex]
Zatem bok
[tex]150 = a \times 12 | \div 12 \\ a = 12.5[/tex]
4.
Obwód
[tex]2(8 + 6) = 16 + 12 = 28cm[/tex]
Zatem bok kwadratu
[tex]4a = 28 | \div 4 \\ a = 7cm[/tex]
Pole prostokąta
[tex]8 \times 6 = 48 {cm}^{2} [/tex]
Pole kwadratu
[tex]7 \times 7 = 49 {cm}^{2} [/tex]
Różnica
[tex]49 - 48 = 1 {cm}^{2} [/tex]
Odpowiedź: Większe pole ma kwadrat. O 1cm²
