[tex]Dane:\\h = 3 \ cm = 0,03 \ m\\d = 13 \ 600\frac{kg}{m^{3}} \ - \ gestosc \ rteci\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h\\\\p = 13 \ 600\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,03 \ m\\\\\boxed{p = 4 \ 080 \ Pa = 4,08 \ kPa}\\\\(1 \ kPa = 1000 \ Pa)[/tex]
