Odpowiedź:
a)
4a
4 × [tex]\frac{3}{4}[/tex] = 3
b) 2a + b
2 × 1[tex]\frac{1}2} + 3[/tex] = 6
c) m - 1[tex]\frac{1}{2}[/tex]
[tex]4\frac{1}{6} - 1\frac{1}{2} = 4\frac{1}{6} - 1\frac{3}{6} = 2\frac{4}{6} = 2\frac{2}{3}[/tex]
d) 2y
2 × [tex]1 \frac{1}{5} = \\[/tex] 2 ×[tex]\frac{6}{5}[/tex] = [tex]\frac{12}{5} = 2\frac{2}{5}[/tex]
e) 3a : 4
3 × 2[tex]\frac{2}{5}[/tex] : 4 = 3 × [tex]\frac{12}{5}[/tex]: 4 = [tex]\frac{36}{5}[/tex]×[tex]\frac{1}{4}[/tex]= [tex]\frac{9}{5}= 1\frac{4}{5}[/tex]
f) 3b+2[tex]\frac{5}{6}[/tex]
3 × [tex]\frac{10}{9} + \frac{17}{6}[/tex]= [tex]\frac{30}{9} + \frac{17}{6} = \frac{60}{18} + \frac{51}{18} = \frac{111}{18} = 6\frac{3}{18} = 6\frac{1}{6}[/tex]
