[tex]a)\\\\0,75:3+ 1,28:0,04- 2\frac{1}{4}(3,5- 2\frac{1}{3})+1,65=\\\\\\=\frac{75}{100}*\frac{1}{3} +\frac{128}{100}:\frac{4}{100}-\frac{9}{4}*(\frac{35}{10}-\frac{7}{3})+1,65=\\\\\\=\frac{\not{3}^1}{4}*\frac{1}{\not{3}^1} +\frac{\not{128}^{32} }{\not{100}^1}*\frac{\not{100}^1}{\not{4}^1}-\frac{9}{4}*(\frac{7}{2}-\frac{7}{3})+1,65= \frac{1}{4} +32-\frac{9}{4}(\frac{21}{6}-\frac{14}{6})+1\frac{65}{100 }=[/tex]
[tex]= \frac{1}{4} +32-\frac{\not{9}^3}{4}*\frac{7}{\not{6}^2} +1\frac{13}{20}=32\frac{1}{4} -\frac{21}{8}+1\frac{13}{20}=32\frac{10}{40} -2\frac{5}{8}+1\frac{26}{40}=\\\\=33\frac{36}{40} -2\frac{25}{40} = 31\frac{11}{40}[/tex]
[tex]b)\\\\(2,5-1\frac{2}3{}):1\frac{7}{8} -( \frac{1}{3})^2+ 1,25:0,05 - 16,8=\\\\=(\frac{25}{10}- \frac{5}3{}): \frac{15}{8} - \frac{1}{9} + \frac{125}{100}: \frac{5}{100} - 16 \frac{8}{10}= \\\\=(\frac{ 5}{2}- \frac{5}{3})*\frac{8}{15} - \frac{1}{9} + \frac{\not{125}^{25}}{\not{100}^1}* \frac{\not{100}^1}{\not{5}^1} - 16 \frac{4}{5}=[/tex]
[tex]=(\frac{15}{6}- \frac{10} {6})*\frac{8}{15} - \frac{1}{9} + 25 - 16 \frac{4}{5}= \frac{\not{5}^1}{\not{6}^3}*\frac{\not{8}^4}{\not{15}^3} +24\frac{8}{9} -16\frac{4}{5}=\\\\= \frac{4}{9}+24\frac{8}{9} -16\frac{4}{5}=24\frac{12}{9}-16\frac{4}{5}=2 5\frac{3}{9}-16\frac{4}{5}= 25\frac{1}{3}-16\frac{4}{5}= \\\\= 25\frac{ 5}{15}-16\frac{12}{15}= 24\frac{ 20}{15}-16\frac{12}{15}= 8\frac{8}{15}[/tex]
[tex]c)\\\\1\frac{1}{4}:0,5 +0,954 :0,09 -3\frac{1}{2}*(2\frac{7}{8}-1,275)+2,6 =\\\\= \frac{5}{4}:\frac{ 5}{10} + \frac{954}{1000} :\frac{ 9 }{100}- \frac{7}{2}*( \frac{23}{8}-\frac{1275}{1000})+2, 6 =\\\\= \frac{\not{5}^1}{\not{4}^2}*\frac{\not{10}^5}{ \not{5}^1} + \frac{\not{477}^{53}}{\not{500}^{ 5}}*\frac{\not{100}^1}{ \not{9}^1 }- \frac{7}{2}*( \frac{23}{8}-\frac{ 51}{40})+2, 6 =[/tex]
[tex]=\frac{5}{2} +\frac{53}{5} -\frac{7}{2}* (\frac{115}{40}-\frac{51}{40 })+2,6=\frac{25}{10} +\frac{106}{10} -\frac{7}{2}* \frac{64}{40} +2,6=\frac{131}{10}-\frac{7}{2}*\frac{8}{5}+\frac{26}{10}=\\\\=\frac{131}{10}- \frac{56}{10 }+\frac{26}{10}=\frac{75}{10}+\frac{26}{10}=\frac{101}{10}=10,1[/tex]
