Odpowiedź :
Pole
[tex] \frac{(a + b) \times h}{2} [/tex]
[tex] \frac{(2x + x) \times 6}{2} = \frac{3x \times 6}{2} = 3x \times 3 = 9x[/tex]
Dla x=9
[tex]9 \times 9 = 81[/tex]
Obwód
[tex]2x + x + 2(x - 1.5) = 3x + 2x - 3 = 5x - 3[/tex]
Dla x=9
[tex]5 \times 9 - 3 = 45 - 3 = 42[/tex]
P=
[tex] \frac{h(a + b)}{2} = \frac{6(x + 2x)}{2} = \frac{18x}{2} = 9x = 9 \times 9 = 81 [/tex]
Ob=
2x+x+x-1.5+x-1.5=5x-3=45-3=42