[tex]Dane:\\t_1 = 10 \ min = 10\cdot60 \ s = 600 \ s\\s_1 = 300 \ m\\t_2 = 15 \ min = 15\cdot60 \ s = 900 \ s\\s_2 = 600 \ m\\\\Rozwiazanie\\\\v_{sr} = \frac{s_{c}}{t_{c}}\\\\s_{c} = s_1+s_2 = 300 \ m +600 \ m = 900 \ m\\t_{c} = t_1 + t_2 = 600 \ s + 900 \ s = 1500 \ s\\\\v_{sr} = \frac{900 \ m}{1500 \ s}\\\\\boxed{v_{sr} = 0,6\frac{m}{s}}[/tex]
Odp. Prędkość średnia wynosi 0,6 m/s.
