[tex]Dane:\\h = 10 \ cm = 0,1 \ m\\d = 14 \ 000\frac{kg}{m^{3}} \ - \ gestosc \ rteci\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h\\\\p = 14000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,1 \ m\\\\p = 14 \ 000 \ \frac{N}{m^{2}}\\\\\frac{1 \ N}{1 \ m^{2}} = 1 \ Pa\\\\\boxed{p = 14 \ 000 \ Pa = 14 \ kPa}[/tex]
