[tex]5\frac{3}{4} - \frac{3}{4}*(4 \frac{2}{5}- 3 \frac{4} {10} )-2 \frac{3}{8}+ (3 \frac{1}{4}-1 \frac{2}{3})=\\\\=5\frac{3}{4} - \frac{3}{4}*(4 \frac{4}{10}- 3 \frac{4} {10} )-2 \frac{3}{8}+ (3 \frac{3}{12}-1 \frac{8}{12})= \\\\=5\frac{3}{4} - \frac{3}{4}* 1-2 \frac{3}{8}+ 1 \frac{7}{12} = 5\frac{18}{24} - \frac{18}{24} -2 \frac{9}{24}+ 1 \frac{14}{ 24} =\\\\=5-2\frac{9}{24}+1\frac{14}{24}=2\frac{15}{24}+1\frac{14}{24}=3\frac{29}{24}= 4\frac{5}{24}[/tex]
