Odpowiedź :
1)
[tex]8\frac{5}{8}+\frac{1}{2}b=15\frac{1}{2}\\\\\frac{1}{2}b=15\frac{1}{2}-8\frac{5}{8}=15\frac{4}{8}-8\frac{5}{8}=14\frac{12}{8}-8\frac{5}{8}\\\\\frac{1}{2}b=6\frac{7}{8}\\\\b=6\frac{7}{8}\cdot2=\frac{6\cdot8+7}{8}\cdot2=\frac{48+7}{8}\cdot2=\frac{55}{8}\cdot2=\frac{55}{4}\\\\\boxed{b=13\frac{3}{4}}[/tex]
2)
[tex]d:4=5\frac{1}{2}\\\\d=5\frac{1}{2}\cdot4=\frac{5\cdot2+1}{2}\cdot4=\frac{10+1}{2}\cdot4=\frac{11}{2}\cdot4=11\cdot2\\\\\boxed{d=22}[/tex]
3)
[tex]6:c=1\frac{1}{2}\\\\c=6:1\frac{1}{2}=6:\frac{1\cdot2+1}{2}=6:\frac{2+1}{2}=6:\frac{3}{2}=6\cdot\frac{2}{3}=2\cdot2\\\\\boxed{c=4}[/tex]