Odpowiedź :
[tex]zad.16\\\\H=4~[j]\\\\P_{p} =\dfrac{1}{2} \cdot a\cdot h~~gdzie~~a=2~[j],~~h=3~[j]\\\\P_{p} =\dfrac{1}{2} \cdot 2~[j]\cdot 3~[j] =3~[j^{2} ]\\\\V=\dfrac{1}{3} \cdot P_{p} \cdot H\\\\V= \dfrac{1}{3} \cdot 3~[j^{2} ] \cdot 4~[j]\\\\V=4~[j^{3} ]\\\\Odp:~~A[/tex]
[tex]zad.17\\\\H=2~[j]\\\\P_{p} =2\cdot 2 ~[j^{2} ]=4~[j^{2} ]\\\\V=\dfrac{1}{3} \cdot 4~[j^{2} ] \cdot 2~[j]\\\\V=\dfrac{8}{3} ~[j^{3} ]=2\dfrac{2}{3} ~[j^{3} ]\\\\Odp_{I} :~~NIE\\\\P_{b} =2\cdot \dfrac{1}{2} \cdot 2 \cdot 2 + 2\cdot \dfrac{1}{2} \cdot 2\sqrt{2} \cdot 2\\\\P_{b} = 4+4\sqrt{2} \\\\P_{b} ==4\cdot (1+\sqrt{2} )~[j^{2} ]\\\\Odp_{II} :~~TAK[/tex]
[tex]zad.18\\\\V=48~cm^{3} \\\\P_{p} =4cm\cdot 4cm = 16~cm^{2} \\\\V=\dfrac{1}{3} \cdot P_{p} \cdot H ~~\Rightarrow~~H=\dfrac{3V}{P_{p} } \\\\H=\dfrac{3\cdot 48~cm^{3} }{16~cm^{2} } \\\\H=9~cm\\\\Odp:~~D[/tex]