Odpowiedź:
a)
[tex]\frac{2}{5(3-x)-2} = \frac{2}{15 - x -2} = \frac{2}{13 - x}[/tex]
b)
[tex]\frac{1-6}{7-x} = \frac{4}{7}[/tex]
4(7-x) = (1 - 6)7
28 - 4x = - 35
-4x = - 63
x = 15,75
c)
[tex]\frac{2x+3}{5}=\frac{2-x}{3}[/tex]
3(2x + 3) = 5(2 - x)
6x + 9 = 10 - 5x
11x = 1
[tex]x = \frac{1}{11}[/tex]
d)
3(x + 6)2(x-9) = 6(x + 6)(x - 9) = 6(x² + 6x - 9x - 54) = 6(x² - 3x - 54) =
= 6x² - 18x -324
