Zadanie w załączniku



Zadanie W Załączniku class=

Odpowiedź :

f)

[tex]\frac{1}{3} : 0.6 + 625 : 100 -4\frac{1}{3} - \frac{1}{3} * (3.6-1\frac{2}{3})+2\frac{3}{4}=\\\frac{1}{3} : \frac{3}{5} + 6.25 -\frac{13}{3}-\frac{1}{3}*(\frac{18}{5}-\frac{5}{3})+\frac{11}{4}=\\\frac{1}{3}*\frac{5}{3}+\frac{25}{4}-\frac{13}{3}-\frac{1}{3}*\frac{29}{15}+\frac{11}{4}=\\\frac{5}{9}+\frac{25}{4}-\frac{13}{3}-\frac{29}{45}+\frac{11}{4}=\\\frac{206}{45} = 4\frac{26}{45}[/tex]

g)

[tex]1\frac{1}{3} : 1.6 - 1.05 : 1.5 +3.5 + (3.8 - 2\frac{3}{5})+ 0.75=\\\frac{4}{3}:\frac{8}{5}-0.7+3.5+(\frac{19}{5}-\frac{13}{5})+0.75=\\\frac{4}{3}*\frac{5}{8}-0.7+3.5+\frac{6}{5}+0.75=\\\frac{1}{3}*\frac{5}{2}-0.7+3.5+\frac{6}{5}+0.75=\\\frac{5}{6}-0.7+3.5+\frac{6}{5}+0.75=\\\frac{61}{30} + 3.55=\\\frac{61}{30} + \frac{71}{20}=\\\frac{67}{12}= 5\frac{7}{12}[/tex]