Odpowiedź:
(x-3)(4x+2)=4x2+3
4x^2+2x-12x-6=4x^2+3
4x^2-10x-6=4x^2+3 |-4x^2
-10x-6=3 |+6
-10x=9 |÷(-10)
x= -[tex] \frac{9}{10} [/tex]
Pozdrawiam :)
