[tex]f)\\\\ \frac{1}{5}(y-3)- \frac{2}{3}(y- \frac{3}{5})+ \frac{1}{3} = \frac{2}{5} - \frac{1}{3}(2y-3) )\\\\ \frac{1}{5} y-\frac{3}{5}-\frac{2}{3}y + \frac{2}{5} + \frac{1}{3} = \frac{2}{5} - \frac{2}{3}y+1 \\\\ \frac{1}{5}y -\frac{2}{3}y-\frac{1}{5} + \frac{1}{3} = \frac{2}{5} - \frac{2}{3}y+1 \\\\ \frac{1}{5}y -\frac{2}{3}y + \frac{2}{3}y=\frac{2}{5}+1+\frac{1}{5} - \frac{1}{3}\\\\\frac{1}{5}y=1\frac{3}{5}-\frac{1}{3}[/tex]
[tex]\frac{1}{5}y= \frac{8}{5}-\frac{1}{3} \\\\\frac{1}{5}y= \frac{24}{15}-\frac{5}{15} \\\\\frac{1}{5}y=\frac{19}{15}\ \ |*5\\\\y=\frac{19}{3}=6\frac{1}{3}[/tex]
[tex]g)\\\\\frac{ y-2 }{3}+ \frac{1}{15}- \frac{2y-5}{5}+\frac{1}{3}=\frac{ 8-4y }{5} \ \ |*15\\\\5(y-2)+1-3(2y-5)+5=3(8-4y)\\\\5y-10+1-6y+15+5=24-12y\\\\-y+11 =24-12y \\\\-y+12y=24-11\\\\11y=13\ \ |:11\\\\y=\frac{13}{11}=1\frac{2}{11}[/tex]
[tex]h)\\\\\frac{ y-5}{2}+\frac{ 2y+3 }{5} + \frac{1}{3} =\frac{ y+7 }{15}+\frac{y}{2}\ \ |*30\\\\15(y-5)+6(2y+3)+10=2(y+7)+15y\\\\15y-75+12y+18+10=2y+14+15y\\\\27y-47=17y+14\\\\27y-17y=14+47\\\\10y=61\ \ |:10\\\\y=\frac{61}{10}=6,1[/tex]
