Odpowiedź:
d) [tex]\frac{2x + 3}{5}[/tex] = [tex]\frac{2 - x}{3}[/tex] + x / * 15
3(2x + 3) = 5(2 - x) + x
6x + 9 = 10 - 5x + x
6x + 5 x - x = 10 - 9
10x = 1 /:10
x = [tex]\frac{1}{10}[/tex]
c) [tex]\frac{x + 2}{9}[/tex] + [tex]\frac{x - 1}{3}[/tex] = 1 / *9
x + 2 + 3(x - 1) = 1
x + 2 + 3x - 3 = 1
x + 3x = 1 +3 - 2
4x = 2 /:4
x = [tex]\frac{1}{2}[/tex]
e)[tex]\frac{3x - 5}{2}[/tex] - [tex]\frac{5x - 1}{10}[/tex] = 0 / *10
5(3x - 5) - 5x - 1 = 0
15x - 25 - 5x - 1 = 0
15 x - 5x = 0 + 1 + 25
10x = 26 /:10
x = 2,6
Szczegółowe wyjaśnienie:
