[tex]Dane:\\m =60 \ kg\\S = 80 \ cm\times 30 \ cm = 2400 \ cm^{2} = 0,24 \ m^{2}\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\ale \ \ F = m\cdot g = 60 \ kg\cdot10\frac{N}{kg} = 600 \ N\\\\p = \frac{600 \ N}{0,24 \ m^{2}}\\\\\boxed{p = 2 \ 500 \ Pa = 25 \ hPa}\\\\(1 \ hPa = 100 \ Pa)\\\\\underline{Odp. \ C.}[/tex]
