[tex]\text{Podstawa}\\a = 8cm\\b=17cm\\h=6cm\\\\\text{Bryla}:\\H=20cm[/tex]
[tex]\text{Objetosc: }\\V=Pp*H\\V=\frac{(a+b)*h}2*H\\V=\frac{(8cm+17cm)*6cm}2*20cm=25cm*6cm*10cm=1500cm^3[/tex]
[tex]1dm=10cm\\1dm^3=(10cm)^3=1000cm^3\\1500cm^3=1,5dm^3\\Odp. A[/tex]
[tex]\text{Ramie podstawy: }\\(17cm-8cm):2=4.5cm\\\\(4,5cm)^2+(6cm)^2=c^2\\20.25cm^2+36cm^2=c^2\\56.25cm^2=c^2\\c=\sqrt{56.25cm^2}=7.5cm\\\\\text{Pole powierzchni: }\\Pp=\frac{(8cm+17cm)*6cm}2=25cm*3cm=75cm^2\\Pb=aH+bH+2cH\\Pb=8cm*20cm+17cm*20cm+2*7.5cm*20cm=160cm^2+340cm^2+300cm^3=800cm^2\\Pc=2Pp+Pb\\Pc=2*75cm^2+800cm^2=150cm^2+800cm^2=950cm^2\\\\1dm=10cm\\1dm^2=(10cm)^2=100cm^2\\950cm^2=9.5dm^2\\\\Odp. B[/tex]
