Pole podstawy
[tex]6 \times \frac{ {a}^{2} \sqrt{3} }{4} [/tex]
[tex]6 \times \frac{ {2}^{2} \sqrt{3} }{4} = 6 \times \frac{ \not4 _1\sqrt{3} }{ \not4_1} = 6 \sqrt{3} [/tex]
Objętość
[tex]V = \frac{Pp \times H}{3} [/tex]
[tex]V = \frac{ \not6 _2\sqrt{3} \times 5 }{ \not3_1} = 10 \sqrt{3} [/tex]
