Odpowiedź:
[tex](4a-1)(2-3a)=8a-12a^2-2+3a=-12a^2+11a-2\\\\\\(a^5-1)(a+1)-a^6=a^6+a^5-a-1-a^6=a^5-a-1\\\\\\(2k^2-1)(2k+1)-4k^3=4k^3+2k^2-2k-1-4k^3=2k^2-2k-1\\\\\\(3p^2-p)(3-p)=9p^2-3p^3-3p+p^2=-3p^3+10p^2-3p\\\\\\(a-b)(a^2+ab+b^2)=a^3+a^2b+ab^2-a^2b-ab^2-b^3=a^3-b^3\\\\\\(a+b)(a^2-ab+b^2)=a^3-a^2b+ab^2+a^2b-ab^2+b^3=a^3+b^3[/tex]
