Odpowiedź:
(2ab+a+3)-(3ab-a+3) = 2ab + a + 3 - 3ab +a -3 = -ab + 2a
(4x²-3x)-(x+0,1x²)-(x²-0,1x) = 4x²-3x -x - 0,1x² - x²+0,1x = 2,9x²-3,9x
6(x-4)-2 = 6x-24-2 = 6x - 26
2(x+1) -3(x-1) = 2x+2-3x+3 = -x+5
-3(y-2)+4(y+2) = -3y+6+4y+8= y+14
5(x-y-1) - 4(x+2) = 5x-5y-5-4x-8 = x - 5y -8
2(3a+b) -2(a-b) = 6a+2b-2a+2b = 4a + 4b
1/2(4x-4) - 2x = 2x - 2 - 2x = -2
x(x-1)-3(x²-x) = x² -x -3x²+3x = -2x²+2x
Szczegółowe wyjaśnienie:
