Odpowiedź:
a)
2(3x-5-3)(2+x) = 5-(x+1)
(6x-10-6)(2+x) = 5-x+1
12x-20-12+[tex]6x^{2}[/tex]-10x-6x = 5-x+1
12x-10x-6x+x = 5+1+2-+12-[tex]6x^{2}[/tex]
-3x = 20-[tex]6x^{2}[/tex] /:(-3)
x = [tex]-\frac{3}{20}[/tex]+3[tex]x^{2}[/tex]
b)
[tex]\frac{x}{3}[/tex]-[tex]\frac{1}{2}[/tex] = 3x-[tex]\frac{x-2}{4}[/tex] /*12
4x-6 = 12x-3(x-2)
4x-6 = 12x-3x+6
4x-12x+3x = 6+6
-5x = 12 /:(-5)
x = -[tex]\frac{5}{12}[/tex]
c)
[tex]\frac{2x-1}{2}[/tex]-3x-[tex]\frac{3x-1}{3}[/tex] = 1+[tex]\frac{x-1}{4}[/tex] /*12
6(2x-1)-36x-4(3x-1) = 12+3(x-1)
12x-6-36x-12x+4 = 12+3x-3
12x-36x-12x-3x = 12-3-4
33x = 5 /:33
x = [tex]\frac{5}{33}[/tex]
Szczegółowe wyjaśnienie:
